ATMEGA328p Standalone 8MHz @ 2.5v

i've been reading nick gammon's post ( http://gammon.com.au/power) on power management atmega 328p , having trouble reaching same level of efficiency. configured fuses use internal 8mhz clock , connected 2.5v. according post, should consuming 0.51ma. however, i'm measuring 5ma (yes double checked, says "ma"). loaded script (from nick's post) atmega baseline test.

code: [select]


void setup(){}
void loop(){}


my power supply unregulated.
these fuses read avrdude:
lfuse: 0xe2
hfuse: 0xde
efuse: 0x07

here how have atmega 328p wired:

pin 1: 10k resistor >> 2.5v
pin 7: 2.5v
pin 8: gnd
pin 20: 2.5v
pin 22: gnd
10uf capacitor between 2.5v & gnd

also, temporarily loaded sketch blinks led on digital 13 make sure functioning.

does know doing wrong?

[edit] updated title of thread, said atmega238p rather atmega328p

that's "sketch a" nick's article.  he claims, "running on 5v through +5v pin, draws 46.6 ma."  you're measuring 5 ma expecting 0.51 ma.  he claims: sketch on bare-bones board draws 15.15 ma (which similar configuration).

why expecting current consumption low?  5 ma seems reasonable me @ half clock speed, half voltage, , no external crystal.

or expecting current consumption higher 5 ma , got decimal in wrong place (51 ma versus 0.51 ma)?

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